Difference between revisions of "DateTime subtractYears"
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Revision as of 10:54, 21 March 2011
DateTime_subtractYears
Return datetime after subtracting years
Syntax
DateTime_subtractYears(datetime,n)
Arguments
- datetime: is array which is datetime to be subtracted
- n: is number which is the number of years to be subtracted
Return value
array, in which there are 9 items:
|
Index |
Data type |
Value |
|
DateTime_Year |
number |
Value after the calculation |
|
DateTime_Month |
number |
Value after the calculation |
|
DateTime_Day |
number |
Value after the calculation |
|
DateTime_Hour |
number |
Value after the calculation |
|
DateTime_Minute |
number |
Value after the calculation |
|
DateTime_Second |
number |
Value after the calculation |
|
DateTime_Millisecond |
number |
Value after the calculation |
|
DateTime_Week |
number |
Value after the calculation |
|
DateTime_TimeZone |
number |
Value of input date time object array Example number n = 4; array a1 = {2013,6,15,0,0,0,0,33,40}; //getCurrentDateTime(); array a2 = DateTime_subtractYears(a1,n); print(a2); // a2 = {2009,6,15,0,0,0,0,33,40} Availability Version 5.7
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