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Folder_getFolderByResourceId Syntax Folder_getFolderByResourceId(Folder_resource_id) Arguments Folder_resource_id: Is an expression of the type number. Return type Array Examples array a=Folder_getFolderByResourceId(2128); print(a); // output {28,2128,Administration,1,2071,True,0,False,Administration} Availability Version 5.8