DateTime subtractHours
DateTime_subtractHours
Return datetime after subtracting hours
Syntax
DateTime_subtractHours(datetime,n)
Arguments
- datetime: is array which is datetime to be subtracted
- n: is number which is the number of hours to be subtracted
Return value
array, in which there are 9 items:
Index |
Data type |
Value |
DateTime_Year |
number |
Value after the calculation |
DateTime_Month |
number |
Value after the calculation |
DateTime_Day |
number |
Value after the calculation |
DateTime_Hour |
number |
Value after the calculation |
DateTime_Minute |
number |
Value after the calculation |
DateTime_Second |
number |
Value after the calculation |
DateTime_Millisecond |
number |
Value after the calculation |
DateTime_Week |
number |
Value after the calculation |
DateTime_TimeZone |
number |
Value of input date time object array |
Example
number n = 4;
array a1 = {2009,6,15,4,0,0,0,25,40}; //getCurrentDateTime();
array a2 = DateTime_subtractHours(a1,n);
print(a2);
// a2 = {2009,6,15,0,0,0,0,25,40}
Availability
Version 5.7